thank you so much everyone for explaining it. I got it now!
-James
On 12/11/12 11:50 AM, "vanisaac_at_boil.afraid.org"
<vanisaac_at_boil.afraid.org> wrote:
>From: James Lin <James_Lin_at_symantec.com>
>> Hi
>> Does anyone know why ill-form occurred on the UTF-8? besides it doesn't
>>follow > the pattern of UTF-8 byte-sequences, i just wondering how or
>>why?
>> If i have a code point: U+4E8C or "二"
>> In UTF-8, it's "E4 BA 8C" while in UTF-16, it's "4E8C". Where is this
>>"BA"
>> comes from?
>>
>> thanks
>> -James
>
>Each of the UTF encodings represents the binary data in different ways.
>So we
>need to break the scalar value, U+4E8C, into its binary representation
>before
>we proceed.
>
>4E8C -> 0100 1110 1000 1100
>
>Then, we need to look up the rules for UTF-8. It states that code points
>between U+800 and U+FFFF are encoded with three bytes, in the form
>1110xxxx
>10xxxxxx 10xxxxxx. So plugging in our data, we get
>
> 4 E 8 C
> 0100 1110 10-00 1100
> |||| ||||// \||||
>+ 1110xxxx 10xxxxxx 10xxxxxx
>
>= 11100100 10111010 10001100
>or E 4 B A 8 C
>
>-Van Anderson
Received on Tue Dec 11 2012 - 18:24:23 CST
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