RBNF rule semantics for a ruleset when there is no negative number rule
Philippe Verdy
verdy_p at wanadoo.fr
Fri Dec 2 10:47:30 CST 2016
Note that there should be a negative-number rule there to format the sign
and separately the absolute value 50.
2016-12-02 17:45 GMT+01:00 Philippe Verdy <verdy_p at wanadoo.fr>:
> rule for "4" matches the "Binary-search the rule list for the rule with
> the highest base value less than or equal to the number.", in fact all
> rules for "0", "3" and "4" have a base value less than or equal to the
> number 50. The binary search will point you just above rule for "4", which
> is the highest base value to use.
>
> 2016-12-02 10:52 GMT+01:00 Kip Cole <kipcole9 at gmail.com>:
>
>> I am writing some software using the CLDR. I am stuck on working out the
>> right semantics for formatting a number using RBNF and there is no matching
>> rule within a specified ruleset.
>>
>> For example (I’m writing this in Elixir but I think the intent is clear)
>> formatting the negative integer -50 in the locale “hr”:
>>
>> iex> Cldr.Rbnf.Spellout.spellout_ordinal_neuter(-50, "hr”)
>>
>> returns an error because in the locale “hr”, the ruleset for
>> spellout-ordinal-neuter has the following rules (in 30.0.2, using the json
>> github content):
>>
>> "%spellout-ordinal-neuter": {
>> "0": "=%%spellout-ordinal-base=o;",
>> "3": "=%%spellout-ordinal-base=e;",
>> "4": "=%%spellout-ordinal-base=o;"
>> }
>>
>> So that by my understanding, a negative number can’t be formatted in this
>> ruleset for this locale. The nearest understanding I can get is from
>> http://www.icu-project.org/apiref/icu4c/classRuleBasedNumberFormat.html
>> which says:
>>
>> • If the number is negative, use the negative-number rule.
>> • If the number has a fractional part and is greater than 1, use
>> the improper fraction rule.
>> • If the number has a fractional part and is between 0 and 1, use
>> the proper fraction rule.
>> • Binary-search the rule list for the rule with the highest base
>> value less than or equal to the number. If that rule has two substitutions,
>> its base value is not an even multiple of its divisor, and the number is an
>> even multiple of the rule's divisor, use the rule that precedes it in the
>> rule list. Otherwise, use the rule itself.
>>
>> Given a negative integer in this context then:
>>
>> 1. There is no negative number rule
>> 2. There is no rule that satisfies "Binary-search the rule list for the
>> rule with the highest base value less than or equal to the number.”
>>
>> Are then any additional semantics intended to cover this case or is an
>> error the appropriate response?
>>
>> Many thanks.
>> _______________________________________________
>> CLDR-Users mailing list
>> CLDR-Users at unicode.org
>> http://unicode.org/mailman/listinfo/cldr-users
>>
>
>
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