What I had sent out was originially rich text, and I had missed a base-16
subscript, which led to what looks like an error. The line
> C3 = (U mod 100016) \ x40 + x80
should read
> C3 = (U mod x1000) \ x40 + x80
Peter
On 11/14/2001 10:15:06 AM Peter Constable wrote:
>A week or so ago, I asked for comments on a C++ algorithm for converting
>UTF-32 to UTF-8. There were a couple of things pointed out to me that had
>to do with the pseudo-code algorithm I provided to the developer. Here's
a
>revised pseudo-code algorithm:
>
>U is a Unicode scalar value; C1, C2, etc. are byte code units in a UTF-8
>sequence; and \ is integer divide.
>
>If U <= U+007F, then
> C1 = U
>Else if U+0080 <= U <= U+07FF, then
> C1 = U \ x40 + xC0
> C2 = U mod x40 + x80
>Else if U+0800 <= U <= U+D7FF, or if U+E000 <= U <= U+FFFF, then
> C1 = U \ x1000 + xE0
> C2 = (U mod x1000) \ x40 + x80
> C3 = U mod x40 + x80
>Else if U >= U+FFFF, then
> C1 = U \ x40000 + xF0
> C2 = (U mod x40000) \ x1000 + x80
> C3 = (U mod 100016) \ x40 + x80
> C4 = U mod x40 + x80
>Else
> Error
>End if
>
>
>- Peter
>
>
>---------------------------------------------------------------------------
>Peter Constable
>
>Non-Roman Script Initiative, SIL International
>7500 W. Camp Wisdom Rd., Dallas, TX 75236, USA
>Tel: +1 972 708 7485
>E-mail: <peter_constable@sil.org>
>
>
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