Re: Question about the replacement of Greek extended characters (u1F..) by equivalent Greek ones (u03..)

From: Eric Muller (emuller@adobe.com)
Date: Thu Aug 23 2007 - 11:27:18 CDT

  • Next message: Asmus Freytag: "Re: Apostrophes at www.unicode.org"

    Ginette Beurton wrote:
    >
    > For example, u03AF is not declared as an equivalent of u1F71. So the
    > relation between the 2 codes is not symmetric.

    Actually, the interesting relation is symmetric (well, for 03A*C* and 1F71).

    What you see in the code charts is this:

    - U+03AC ά GREEK SMALL LETTER ALPHA WITH TONOS

    - U+1F71 ά GREEK SMALL LETTER ALPHA WITH OXIA
        (decomposes to) U+03AC ά GREEK SMALL LETTER ALPHA WITH TONOS

    The last line records the canonical decomposition *mapping* of U+1F71
    into <U+03AC>, and there is indeed no corresponding canonical
    decomposition mapping of U+03AC.

    But the decomposition mappings are only building blocks for the notion
    you are looking for, which is canonical *equivalence*. In other words,
    the decomposition mappings are not too interesting in themselves, what
    matters is whether two strings are canonically equivalent and the
    strings <03AC> and <1F71> are canonically equivalent. UAX 15
    (<http://www.unicode.org/reports/tr15/>) has all the details.

    Eric.
     

    This archive was generated by hypermail 2.1.5 : Thu Aug 23 2007 - 11:29:00 CDT