on 4/11/2000 7:44 PM, Mike Brown <firstname.lastname@example.org> wrote:
> Here is what I am trying:
> 1. U+2022 = hex 2022
> 2. hex 2022 = binary octets 00100000 00100010
> 3. those octets are divided into sextets with zero-padding out to 24 bits as
> per the RFCs. I'll use "o" here to represent the 0's used for padding:
> 001000 000010 0010oo oooooo
> 4. the scalar values of these octets: 8 2 8 0
> 5. those values are indexes into the array of [encoded] characters in the
> Base64 alphabet: I C I A
> So I don't see how "+ICI" is well-formed and "+ICIA" isn't. I also don't see
> how you could ever have less than 4 characters in a Modified Base64
> representation of a single Unicode character.
> What am I missing?
You are confusing octets in the input stream with output Base64 characters.
The RFC does not say an even number of Base64 characters is required, only
an even number of *input* octets (i.e., UTF-16). The RFC also doesn't say
that the output is padded to an octet boundary; it's padded to a Base64
So, to use your example:
2. binary 00100000 00100010
3. Divide into sextets, padding to a *sextet* boundary: 001000 000010 0010oo
4. Scalar values 8 2 8
5. Base64: I C I
Does that make it more clear?
Manager, International Toolbox Group
Apple Computer, Inc.
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